integral from 0 to 4-z^2 of z

Lösung

\int_{0}^{4 - z^{2}} z d z

\frac{( - z ^{2} + 4 ) ^{2}}{2}

Schritte zur Lösung

\int_{0}^{4 - z^{2}} z d z

Wende die Potenzregel an

= [\frac{z ^{2}}{2}]_{0}^{4 - z^{2}}

Berechne die Grenzen:

\frac{1}{2} (- z^{2} + 4)^{2}

= \frac{1}{2} (- z^{2} + 4)^{2}

Vereinfache

= \frac{( - z ^{2} + 4 ) ^{2}}{2}

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