integral from-pi to 0 of sin(θ)

Lösung

\int_{- π}^{0} sin (θ) d θ

- 2

Schritte zur Lösung

\int_{- π}^{0} sin (θ) d θ

Nutze das gemeinsame Integral :

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{- π}^{0}

Berechne die Grenzen:

- 2

= - 2

\int_{1}^{3} (\frac{9}{13} x^{2} - 2) d x

\int_{0}^{1} (3 x + 4) e^{2 x} d x

\int_{- 3}^{1} 2 x - 3 d x

\int_{- 1}^{3} 2 x^{2} - 4 x - 6 d x

\int_{0}^{9} (x + \frac{1}{2}) d x