integral from 0 to 1 of f(u)

Lösung

\int_{0}^{1} f (u) d u

\frac{f}{2}

Schritte zur Lösung

\int_{0}^{1} f u d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{1} u d u

Wende die Potenzregel an

= f [\frac{u ^{2}}{2}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{2}

= f \frac{1}{2}

Vereinfache

= \frac{f}{2}

\int_{1}^{6} \frac{8}{x} d x

\int_{- x}^{x} 1 + t^{2} d t

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