integral from-1 to 2 of (x-4x+3)

Lösung

\int_{- 1}^{2} (x - 4 x + 3) d x

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

\int_{- 1}^{2} x - 4 x + 3 d x

Vereinfache

= \int_{- 1}^{2} - 3 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{2} 3 x d x + \int_{- 1}^{2} 3 d x

\int_{- 1}^{2} 3 x d x = \frac{9}{2}

\int_{- 1}^{2} 3 d x = 9

= - \frac{9}{2} + 9

Vereinfache

- \frac{9}{2} + 9 : \frac{9}{2}

= \frac{9}{2}

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