integral from 0 to (3pi)/2 of 2sin(x)

Lösung

\int_{0}^{\frac{3 π}{2}} 2 sin (x) d x

2

Schritte zur Lösung

\int_{0}^{\frac{3 π}{2}} 2 sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{\frac{3 π}{2}} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= 2 [- cos (x)]_{0}^{\frac{3 π}{2}}

Berechne die Grenzen:

1

= 2 \cdot 1

Vereinfache

= 2

\int_{2}^{5} cos (x) + e^{x} - 2 x d x

\int_{1}^{2} x^{2} - 2 x + 3 d x

\int_{5}^{5} 1

\int_{0}^{1} x^{2} (3 - 10 x^{3})^{4} d x

\int_{- 1}^{1} cos^{2} (x) d x