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人気のある微分積分 >

integral from 0 to 1 of (9x^e+4e^x)

解

\int_{0}^{1} (9 x^{e} + 4 e^{x}) d x

解

\frac{9}{e + 1} + 4 (e - 1)

+1

十進法表記

9.29360 \dots

解答ステップ

\int_{0}^{1} 9 x^{e} + 4 e^{x} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 9 x^{e} d x + \int_{0}^{1} 4 e^{x} d x

\int_{0}^{1} 9 x^{e} d x = \frac{9}{e + 1}

\int_{0}^{1} 4 e^{x} d x = 4 (e - 1)

= \frac{9}{e + 1} + 4 (e - 1)

グラフ

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