What is the integral from 0 to 1 of \sqrt[4]{x}-1 ?

The integral from 0 to 1 of \sqrt[4]{x}-1 is -1/5

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integral from 0 to 1 of \sqrt[4]{x}-1

\int_{0}^{1} 4 x - 1 d x

- \frac{1}{5}

Decimal

- 0.2

Solution steps

\int_{0}^{1} 4 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x d x - \int_{0}^{1} 1 d x

\int_{0}^{1} 4 x d x = \frac{4}{5}

\int_{0}^{1} 1 d x = 1

= \frac{4}{5} - 1

Simplify

\frac{4}{5} - 1 : - \frac{1}{5}

= - \frac{1}{5}

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What is the integral from 0 to 1 of \sqrt[4]{x}-1 ?
The integral from 0 to 1 of \sqrt[4]{x}-1 is -1/5