integral from 100 to 200 of 5+3/(x+2)

Lösung

\int_{100}^{200} 5 + \frac{3}{x + 2} d x

500 + 3 ln (\frac{101}{51})

Dezimale

502.04988 \dots

Schritte zur Lösung

\int_{100}^{200} 5 + \frac{3}{x + 2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{100}^{200} 5 d x + \int_{100}^{200} \frac{3}{x + 2} d x

\int_{100}^{200} 5 d x = 500

\int_{100}^{200} \frac{3}{x + 2} d x = 3 ln (\frac{101}{51})

= 500 + 3 ln (\frac{101}{51})

\int_{1}^{e} 3 t^{2} ln (t) d t

\int_{- 2}^{3} (8 x - 4) d x

\int_{- 6 π}^{6 π} cos^{2} (x) d x

\int_{1}^{e} \frac{t ^{6} + 1}{t} d t

\int_{0}^{π} (2 e^{x} + 3 sin (x)) d x