What is the integral from 6 to 7 of 1 ?

The integral from 6 to 7 of 1 is 1

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integral from 6 to 7 of 1

\int_{6}^{7} 1

1

Solution steps

\int_{6}^{7} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{6}^{7}

Simplify

= [x]_{6}^{7}

Compute the boundaries:

1

= 1

\int_{- 1}^{1} x^{3} - \frac{3}{5} x d x

\int_{1}^{2} (x + 1)^{2} d x

\int_{- 2}^{0} x^{3} 16 - x^{4} d x

\int_{0}^{1} x^{2} 3 x^{3} + 1 d x

\int_{- 3}^{4} x^{2} + sin (x) + e^{x} d x