What is the integral from x^1 to x^2 of 1 ?

The integral from x^1 to x^2 of 1 is x^2-x

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integral from x^1 to x^2 of 1

\int_{x^{1}}^{x^{2}} 1 d x

x^{2} - x

Solution steps

\int_{x^{1}}^{x^{2}} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{x^{1}}^{x^{2}}

Simplify

= [x]_{x}^{x^{2}}

Compute the boundaries:

x^{2} - x

= x^{2} - x

\int_{1}^{2} x + 1 d x

\int_{0}^{\infty} e^{- b x^{2}} d x

\int_{- 3}^{5} (2 x + 15) - x^{2} d x

\int_{- 1}^{1} \frac{( 3 e ^{x} )}{1 + e ^{x}} d x

\int_{0}^{1} 6 x^{5} (9 - x^{6}) d x

What is the integral from x^1 to x^2 of 1 ?
The integral from x^1 to x^2 of 1 is x^2-x