integral from 0 to 1 of 8t^2

Lösung

\int_{0}^{1} 8 t^{2} d t

\frac{8}{3}

Dezimale

2.66666 \dots

Schritte zur Lösung

\int_{0}^{1} 8 t^{2} d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{1} t^{2} d t

Wende die Potenzregel an

= 8 [\frac{t ^{3}}{3}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{3}

= 8 \cdot \frac{1}{3}

Vereinfache

= \frac{8}{3}

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