integral from cot(x) to 0 of 1/(1+t^2)

Lösung

\int_{c o t (x)}^{0} \frac{1}{1 + t ^{2}} d t

- arctan (cot (x))

Schritte zur Lösung

\int_{c o t (x)}^{0} \frac{1}{1 + t ^{2}} d t

Nutze das gemeinsame Integral :

\int \frac{1}{1 + t ^{2}} d t = arctan (t)

= [arctan (t)]_{c o t (x)}^{0}

Berechne die Grenzen:

- arctan (cot (x))

= - arctan (cot (x))

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