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Popular >

integral from 1 to 4 of (x^2-x)

Solution

\int_{1}^{4} (x^{2} - x) d x

Solution

\frac{27}{2}

+1

Decimal

13.5

Solution steps

\int_{1}^{4} x^{2} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x - \int_{1}^{4} x d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} x d x = \frac{15}{2}

= 21 - \frac{15}{2}

Simplify

21 - \frac{15}{2} : \frac{27}{2}

= \frac{27}{2}

Graph

Popular Examples

integral from (-pi)/2 to pi/2 of cos(2x)

\int_{\frac{- π}{2}}^{\frac{π}{2}} cos (2 x) d x

integral from-1 to 4 of 1/(x^2+x-2)

\int_{- 1}^{4} \frac{1}{x ^{2} + x - 2} d x

integral from 2 to 6 of 3

\int_{2}^{6} 3 d x

integral from 0 to 3 of 3x^2-3

\int_{0}^{3} 3 x^{2} - 3 d x

integral from 0 to 2 of (3-x)sqrt(x)

\int_{0}^{2} (3 - x) x d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (x^2-x) ?
The integral from 1 to 4 of (x^2-x) is 27/2