integral from 0 to 1 of sin(t)cos(t)

Lösung

\int_{0}^{1} sin (t) cos (t) d t

\frac{sin ^{2} ( 1 )}{2}

Dezimale

0.35403 \dots

Schritte zur Lösung

\int_{0}^{1} sin (t) cos (t) d t

Wende U-Substitution an

= \int_{0}^{s i n (1)} u d u

Wende die Potenzregel an

= [\frac{u ^{2}}{2}]_{0}^{s i n (1)}

Berechne die Grenzen:

\frac{sin ^{2} ( 1 )}{2}

= \frac{sin ^{2} ( 1 )}{2}

\int_{- 1}^{0} \frac{x}{x ^{2} + 1} d x

\int_{1}^{2} \frac{1}{3 x - 1} d x

\int_{0}^{22} π (x)^{2} d x

\int_{2}^{3} \frac{x + 2}{x - 1} d x

\int_{1}^{- 1} (x^{2} - 1) d x