integral from 2 to 8 of (4x-9)^{20}

Lösung

\int_{2}^{8} (4 x - 9)^{20} d x

\frac{2 3 ^{21} + 1}{84}

Dezimale

4.699 E 26

Schritte zur Lösung

\int_{2}^{8} (4 x - 9)^{20} d x

Wende U-Substitution an

= \int_{- 1}^{23} \frac{u ^{20}}{4} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{- 1}^{23} u^{20} d u

Wende die Potenzregel an

= \frac{1}{4} [\frac{u ^{21}}{21}]_{- 1}^{23}

Berechne die Grenzen:

\frac{2 3 ^{21}}{21} + \frac{1}{21}

= \frac{1}{4} (\frac{2 3 ^{21}}{21} + \frac{1}{21})

Vereinfache

= \frac{2 3 ^{21} + 1}{84}

\int_{\frac{3 π}{2}}^{2 π} cos (θ) d θ

\int_{- 1}^{0} \frac{1}{2 + x} d x

\int_{1}^{3} \frac{2 x}{x ^{2} + 3} d x

\int_{- 1}^{3} 4 x - 3 d x

\int_{- 1}^{6} 3 d x