What is the integral from 0 to 24 of sin(sqrt(x)) ?

The integral from 0 to 24 of sin(sqrt(x)) is 2(sin(2sqrt(6))-2sqrt(6)cos(2sqrt(6)))

Popular >

integral from 0 to 24 of sin(sqrt(x))

\int_{0}^{24} sin (x) d x

2 (sin (26) - 26 cos (26))

Decimal

- 3.78290 \dots

Solution steps

\int_{0}^{24} sin (x) d x

Apply u-substitution

: \int_{0}^{26} sin (u) \cdot 2 u d u

= \int_{0}^{26} sin (u) \cdot 2 u d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{26} sin (u) u d u

Apply Integration By Parts

: [- u cos (u) - \int - cos (u) d u]_{0}^{26}

= 2 [- u cos (u) - \int - cos (u) d u]_{0}^{26}

\int - cos (u) d u = - sin (u)

= 2 [- u cos (u) - (- sin (u))]_{0}^{26}

Simplify

= 2 [- u cos (u) + sin (u)]_{0}^{26}

Compute the boundaries:

sin (26) - 26 cos (26)

= 2 (sin (26) - 26 cos (26))

\int_{0}^{l n (3)} e^{5 x} d x

\int_{0}^{3} ∣ 3 x - 2 ∣ d x

\int_{- 1}^{2} x^{2} + e^{2 x} d x

\int_{- 2}^{3} (2 x^{4} + 5 x^{3} - x + 5) d x

\int_{- 2}^{0} x 2 x^{2} + 1 d x

What is the integral from 0 to 24 of sin(sqrt(x)) ?
The integral from 0 to 24 of sin(sqrt(x)) is 2(sin(2sqrt(6))-2sqrt(6)cos(2sqrt(6)))