What is the integral from-x to x of (t^3+t) ?

The integral from-x to x of (t^3+t) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-x to x of (t^3+t)

\int_{- x}^{x} (t^{3} + t) d t

0

Solution steps

\int_{- x}^{x} t^{3} + t d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

t^{3} + t :

Odd

= 0

\int_{0}^{1} 5 x 2 x + 9 d x

\int_{0}^{2} x^{2} - x + 1 d x

\int_{0}^{3} k x d x

\int_{x^{2}}^{0} (t - t^{2}) d t

\int_{0}^{1} \frac{e - 1}{2 e} d x

What is the integral from-x to x of (t^3+t) ?
The integral from-x to x of (t^3+t) is 0