integral from 1 to 2 of 8/(3x^3)

Lösung

\int_{1}^{2} \frac{8}{3 x ^{3}} d x

1

Schritte zur Lösung

\int_{1}^{2} \frac{8}{3 x ^{3}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{8}{3} \cdot \int_{1}^{2} \frac{1}{x ^{3}} d x

Wende die Potenzregel an

= \frac{8}{3} [- \frac{1}{2 x ^{2}}]_{1}^{2}

Berechne die Grenzen:

\frac{3}{8}

= \frac{8}{3} \cdot \frac{3}{8}

Vereinfache

= 1

\int_{2}^{3} \frac{7}{( 5 x - 5 ) ^{2}} d x

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