integral from-1 to 2 of kx^2

解答

\int_{- 1}^{2} k x^{2} d x

k \cdot 3

求解步骤

\int_{- 1}^{2} k x^{2} d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{- 1}^{2} x^{2} d x

使用幂法则

= k [\frac{x ^{3}}{3}]_{- 1}^{2}

带入上下限计算后得:

3

= k \cdot 3

\int_{- 1}^{0} \frac{1}{x ^{4}} d x

\int_{2}^{1} sin (x) d x

\int_{0}^{2 x + y} 1 d z

\int_{0}^{2} 1 + (e^{x})^{2} d x

\int_{0}^{10} t + 4 d t