integral from 0 to 1.6 of g(x)

Lösung

\int_{0}^{1.6} g (x) d x

g \cdot 1.28

Schritte zur Lösung

\int_{0}^{1.6} gx d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{0}^{1.6} x d x

Wende die Potenzregel an

= g [\frac{x ^{2}}{2}]_{0}^{1.6}

Vereinfache

= g [0.5 x^{2}]_{0}^{1.6}

Berechne die Grenzen:

1.28

= g \cdot 1.28

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