integral from 0 to 2pi of 9

Lösung

\int_{0}^{2 π} 9 d θ

18 π

Dezimale

56.54866 \dots

Schritte zur Lösung

\int_{0}^{2 π} 9 d θ

Integral einer Konstanten :

\int a d x = a x

= [9 θ]_{0}^{2 π}

Berechne die Grenzen:

18 π

= 18 π

\int_{0}^{1} (1 - x^{2})^{\frac{- 1}{2}} d x

\int_{0}^{1} 6 x 4 x^{2} + 1 d x

\int_{0}^{10} e^{- 2 x} d x

\int_{1}^{3} x^{3} + 2 x^{2} - 5 x + 2 d x

\int_{0}^{3} 9 - y^{2} d y