What is the integral from 2 to 4 of g(x) ?

The integral from 2 to 4 of g(x) is g*6

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integral from 2 to 4 of g(x)

\int_{2}^{4} g (x) d x

g \cdot 6

Solution steps

\int_{2}^{4} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{2}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{2}^{4}

= g [\frac{x ^{2}}{2}]_{2}^{4}

Compute the boundaries:

6

= g \cdot 6

\int_{- 2}^{4} (x^{2} + 4)^{3} 4 x d x

\int_{5}^{6} 6 x d x

\int_{a}^{b} x e^{x} d x

\int_{1}^{4} \frac{( 3 x ^{2} + 2 x + 1 )}{x} d x

\int_{0}^{4} x^{3} - 10 x^{2} + 24 x d x

What is the integral from 2 to 4 of g(x) ?
The integral from 2 to 4 of g(x) is g*6