integral from-1 to 2 of (x^3+1)

Lösung

\int_{- 1}^{2} (x^{3} + 1) d x

\frac{27}{4}

Dezimale

6.75

Schritte zur Lösung

\int_{- 1}^{2} x^{3} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x + \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} 1 d x = 3

= \frac{15}{4} + 3

Vereinfache

\frac{15}{4} + 3 : \frac{27}{4}

= \frac{27}{4}

\int_{- 1}^{2} 8 - x^{2} - x d x

\int_{- 2}^{2} 1 - \frac{x ^{2}}{4} d x

\int_{- 2}^{1} 2 x^{2} d x

\int_{- 1}^{1} (x^{2} - x) (x + 1) d x

\int_{0}^{3} - 10 x d x