integral from 8 to 16 of (x+1/x)

Lösung

\int_{8}^{16} (x + \frac{1}{x}) d x

96 + ln (2)

Dezimale

96.69314 \dots

Schritte zur Lösung

\int_{8}^{16} x + \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{8}^{16} x d x + \int_{8}^{16} \frac{1}{x} d x

\int_{8}^{16} x d x = 96

\int_{8}^{16} \frac{1}{x} d x = ln (2)

= 96 + ln (2)

\int_{6}^{7} x^{2} d x

\int_{0}^{1} 19 x e^{x} d x

\int_{1}^{3} \frac{1 + ln ( x ^{3} )}{x} d x

\int_{1}^{8} (\frac{x}{8} - \frac{6}{x}) d x

\int_{1}^{3} \frac{3}{x ^{4}} d x