integral from 0 to 6 of (x^2-3x+4)

Lösung

\int_{0}^{6} (x^{2} - 3 x + 4) d x

42

Schritte zur Lösung

\int_{0}^{6} x^{2} - 3 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} x^{2} d x - \int_{0}^{6} 3 x d x + \int_{0}^{6} 4 d x

\int_{0}^{6} x^{2} d x = 72

\int_{0}^{6} 3 x d x = 54

\int_{0}^{6} 4 d x = 24

= 72 - 54 + 24

Vereinfache

= 42

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