integral from 0 to 1 of x^3-4x

Lösung

\int_{0}^{1} x^{3} - 4 x d x

- \frac{7}{4}

Dezimale

- 1.75

Schritte zur Lösung

\int_{0}^{1} x^{3} - 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x - \int_{0}^{1} 4 x d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} 4 x d x = 2

= \frac{1}{4} - 2

Vereinfache

\frac{1}{4} - 2 : - \frac{7}{4}

= - \frac{7}{4}

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