integral from-2 to 0 of sqrt(|x^3+1|)

解

\int_{- 2}^{0} ∣ x^{3} + 1 ∣ d x

2.35723 \dots

解答ステップ

\int_{- 2}^{0} ∣ x^{3} + 1 ∣ d x

絶対数を排除する

= \int_{- 2}^{- 1} - x^{3} - 1 d x + \int_{- 1}^{0} x^{3} + 1 d x

\int_{- 2}^{- 1} - x^{3} - 1 d x = 1.51592 \dots

= 1.51592 \dots + \int_{- 1}^{0} x^{3} + 1 d x

\int_{- 1}^{0} x^{3} + 1 d x = 0.84130 \dots

= 1.51592 \dots + 0.84130 \dots

1.51592 \dots + 0.84130 \dots = 2.35723 \dots

= 2.35723 \dots