What is the integral from 0 to 8 of 1/(x^{1/3)} ?

The integral from 0 to 8 of 1/(x^{1/3)} is 6

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integral from 0 to 8 of 1/(x^{1/3)}

\int_{0}^{8} \frac{1}{x ^{\frac{1}{3}}} d x

6

Solution steps

\int_{0}^{8} \frac{1}{x ^{\frac{1}{3}}} d x

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{8}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{8}

Compute the boundaries:

6

= 6

\int_{0}^{10} x sin (x^{2}) d x

\int_{0}^{3} \frac{6 y}{y ^{2} + 1} d y

\int_{3}^{e^{x}} (y^{3} sin (y)) d y

\int_{0}^{\frac{π}{2}} 3 cos (x) + 1 d x

\int_{0}^{0.8} cos (x) d x

What is the integral from 0 to 8 of 1/(x^{1/3)} ?
The integral from 0 to 8 of 1/(x^{1/3)} is 6