integral from 0 to x of (x+y)

Lösung

\int_{0}^{x} (x + y) d y

x^{2} + \frac{x ^{2}}{2}

Schritte zur Lösung

\int_{0}^{x} x + y d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{x} x d y + \int_{0}^{x} y d y

\int_{0}^{x} x d y = x^{2}

\int_{0}^{x} y d y = \frac{x ^{2}}{2}

= x^{2} + \frac{x ^{2}}{2}

\int_{3}^{5} (2 x + 1) d x

\int_{- 1}^{3} x^{3} - 3 x^{2} + 5 d x

\int_{- 1}^{1} 3 - x^{2} d x

\int_{0}^{3} \frac{x}{3} e^{x^{2}} d x

\int_{0}^{a} 7 e^{x} d x