What is the integral from 0 to 2 of (2x-x) ?

The integral from 0 to 2 of (2x-x) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 2 of (2x-x)

\int_{0}^{2} (2 x - x) d x

2

Solution steps

\int_{0}^{2} 2 x - x d x

Simplify

= \int_{0}^{2} x d x

Apply the Power Rule

= [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= 2

\int_{5}^{6} \frac{6}{x ^{2}} d x

\int_{0}^{1} 2 π x (3 x (x - 2)^{2}) d x

\int_{- 2}^{2} (- x^{2} - 4) d x

\int_{- 2}^{- 1} \frac{1}{1 + x} d x

\int_{0}^{1} (3 x + 1) d x

What is the integral from 0 to 2 of (2x-x) ?
The integral from 0 to 2 of (2x-x) is 2