integral from 0 to 2pi of-3sin(x)

Lösung

\int_{0}^{2 π} - 3 sin (x) d x

0

Schritte zur Lösung

\int_{0}^{2 π} - 3 sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int_{0}^{2 π} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= - 3 [- cos (x)]_{0}^{2 π}

Berechne die Grenzen:

0

= - 3 \cdot 0

Vereinfache

= 0

\int_{- 2}^{- 1} 4 - x^{2} d x

\int_{1}^{5} (2 x + 1) ln (x + 1) d x

\int_{0}^{x} sin (t^{3}) d t

\int_{1}^{2} 8 - 2 x d x

\int_{\frac{π}{3}}^{π} sin (2 x) d x