(dy)/(dx)=6x^2+3

Lösung

\frac{d y}{d x} = 6 x^{2} + 3

y = 2 x^{3} + 3 x + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = 6 x^{2} + 3

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = 6 x^{2} + 3

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 6 x^{2} + 3 d x

\int 6 x^{2} + 3 d x = 2 x^{3} + 3 x + c_{1}

y = 2 x^{3} + 3 x + c_{1}

in v erse l a pl a ce \frac{( 4 s - 5 )}{s ^{2} - 6 s + 13}

n = 1 \sum \infty (\frac{1}{3})^{n}

a re a 4 x^{2}, \frac{x}{4}

a re a y = x^{2} + 4, y = - x^{2} - 1, x = - 2, x = 3

d er i v a t i v e 30 ln (2 x + 1)