integral from-1 to 2 of 2x^2-2x^3+4x

Lösung

\int_{- 1}^{2} 2 x^{2} - 2 x^{3} + 4 x d x

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

\int_{- 1}^{2} 2 x^{2} - 2 x^{3} + 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 x^{2} d x - \int_{- 1}^{2} 2 x^{3} d x + \int_{- 1}^{2} 4 x d x

\int_{- 1}^{2} 2 x^{2} d x = 6

\int_{- 1}^{2} 2 x^{3} d x = \frac{15}{2}

\int_{- 1}^{2} 4 x d x = 6

= 6 - \frac{15}{2} + 6

Vereinfache

6 - \frac{15}{2} + 6 : \frac{9}{2}

= \frac{9}{2}

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