integral from 0 to 1 of 9x^3

Lösung

\int_{0}^{1} 9 x^{3} d x

\frac{9}{4}

Dezimale

2.25

Schritte zur Lösung

\int_{0}^{1} 9 x^{3} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{1} x^{3} d x

Wende die Potenzregel an

= 9 [\frac{x ^{4}}{4}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{4}

= 9 \cdot \frac{1}{4}

Vereinfache

= \frac{9}{4}

\int_{2}^{0} 3 x (2 - x) d x

\int_{2}^{3} - \frac{4}{x ^{2}} d x

\int_{0}^{1} 1 5^{2 x} d x

\int_{0}^{1} x^{2} 9 - x^{3} d x

\int_{0}^{1} (x^{6} + 1) d x