integral from 0 to 5 of ((x^2)/3+1)

Lösung

\int_{0}^{5} (\frac{x ^{2}}{3} + 1) d x

\frac{170}{9}

Dezimale

18.88888 \dots

Schritte zur Lösung

\int_{0}^{5} \frac{x ^{2}}{3} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} \frac{x ^{2}}{3} d x + \int_{0}^{5} 1 d x

\int_{0}^{5} \frac{x ^{2}}{3} d x = \frac{125}{9}

\int_{0}^{5} 1 d x = 5

= \frac{125}{9} + 5

Vereinfache

\frac{125}{9} + 5 : \frac{170}{9}

= \frac{170}{9}

\int_{- 1}^{1} \frac{x + 2}{56} d x

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