ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 0 to 6 of pi(sqrt(x))^2

解

\int_{0}^{6} π (x)^{2} d x

解

π 18

+1

十進法表記

56.54866 \dots

解答ステップ

\int_{0}^{6} π (x)^{2} d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{6} (x)^{2} d x

簡素化

(x)^{2} : x

= π \cdot \int_{0}^{6} x d x

べき乗則を適用する

= π [\frac{x ^{2}}{2}]_{0}^{6}

限度を計算する:

18

= π 18

グラフ

人気の例

integral from 0 to pi of x^2cos(kx)

\int_{0}^{π} x^{2} cos (k x) d x

integral from 3x to-4 of sin(t^2)

\int_{3 x}^{- 4} sin (t^{2}) d t

integral from 0 to 1 of x17^{x^2}

\int_{0}^{1} x 1 7^{x^{2}} d x

integral from 1 to 2 of (e^{(x-1)})^2

\int_{1}^{2} (e^{(x - 1)})^{2} d x

integral from 5 to 5 of 3x^2(8-x^3)^4

\int_{5}^{5} 3 x^{2} (8 - x^{3})^{4} d x