What is the derivative of arctan(16x) ?

The derivative of arctan(16x) is (16)/(256x^2+1)

What is the first derivative of arctan(16x) ?

The first derivative of arctan(16x) is (16)/(256x^2+1)

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derivative of

arctan (16 x)

\frac{16}{256 x ^{2} + 1}

Solution steps

\frac{d}{d x} (arctan (16 x))

Apply the chain rule:

\frac{1}{( 16 x ) ^{2} + 1} \frac{d}{d x} (16 x)

= \frac{1}{( 16 x ) ^{2} + 1} \frac{d}{d x} (16 x)

\frac{d}{d x} (16 x) = 16

= \frac{1}{( 16 x ) ^{2} + 1} \cdot 16

Simplify

\frac{1}{( 16 x ) ^{2} + 1} \cdot 16 : \frac{16}{256 x ^{2} + 1}

= \frac{16}{256 x ^{2} + 1}

y^{^{'}} = \frac{y + x ^{2} + y ^{2}}{x}

y = 2 x^{3} + 3 x^{2} - 12 x + 6

\int \frac{1}{9 x ^{2}} d x

\frac{\partial}{\partial x} (x^{2} y z^{3} (x - 10 y))

\int arcsec (4 x) d x

What is the derivative of arctan(16x) ?
The derivative of arctan(16x) is (16)/(256x^2+1)
What is the first derivative of arctan(16x) ?
The first derivative of arctan(16x) is (16)/(256x^2+1)