integral of integral of y

解答

\int \int y d y d y

\frac{y ^{3}}{6} + C y + C

求解步骤

\int \int y d y d y

\int y d y = \frac{y ^{2}}{2} + C

= \int (\frac{y ^{2}}{2} + C) d y

\int (\frac{y ^{2}}{2} + C) d y = \frac{y ^{3}}{6} + C y + C

= \frac{y ^{3}}{6} + C y + C

x \to 3 + lim (ln (\frac{1}{x - 3}))

x \to 2 lim (x^{3} - 5 x^{2} + 3 x - 4)

x \to \infty lim (1 + x^{\frac{- 1}{2}} + x^{\frac{- 2}{3}} + x^{\frac{1 - x}{x}})

x \to 1 + lim (\frac{x ^{2}}{ln ( x )})

x \to \frac{π}{2} lim ((sin^{2} (x))^{t a n (x)})