What is the limit as x approaches 0+of 1/(1+2^{1/x)} ?

The limit as x approaches 0+of 1/(1+2^{1/x)} is 0

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limit as x approaches 0+of 1/(1+2^{1/x)}

x \to 0 + lim (\frac{1}{1 + 2 ^{\frac{1}{x}}})

0

Solution steps

x \to 0 + lim (\frac{1}{1 + 2 ^{\frac{1}{x}}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{x \to 0 +} ( 1 )}{lim _{x \to 0 +} ( 1 + 2 ^{\frac{1}{x}} )}

x \to 0 + lim (1) = 1

x \to 0 + lim (1 + 2^{\frac{1}{x}}) = \infty

= \frac{1}{\infty}

Apply Infinity Property:

\frac{c}{\infty} = 0

= 0

x \to 5 lim (\frac{- 3}{x - 5})

x \to 2 - lim ((x - 2) \cdot ln (2 - x))

x \to 0 lim (\frac{x ^{3} - 3 x}{x})

x \to 0 + lim ((e^{2 x} + x)^{\frac{1}{( 3 x )}})

x \to 0 lim (x ln (3 x))

What is the limit as x approaches 0+of 1/(1+2^{1/x)} ?
The limit as x approaches 0+of 1/(1+2^{1/x)} is 0