limit as x approaches 0 of (sin(x-pi))/x

Lösung

x \to 0 lim (\frac{sin ( x - π )}{x})

- 1

Schritte zur Lösung

x \to 0 lim (\frac{sin ( x - π )}{x})

Wende das L'Hopital Theorem an

= x \to 0 lim (\frac{- cos ( x )}{1})

Setze den Wert

x = 0

ein

= \frac{- cos ( 0 )}{1}

Vereinfache

\frac{- cos ( 0 )}{1} : - 1

= - 1

h \to 0 lim (\frac{e ^{h} - 1}{2 h})

h \to 0 lim (cos (h))

x \to - 1 lim (\frac{1 - x ^{4}}{x + 1})

x \to 0 lim (sin (x) - tan (x))

x \to 5 + lim (f (x))