What is the limit as x approaches 0 of ln(x)x^2 ?

The limit as x approaches 0 of ln(x)x^2 is Does not exist

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limit as x approaches 0 of ln(x)x^2

x \to 0 lim (ln (x) x^{2})

Does not exist

Solution steps

x \to 0 lim (ln (x) x^{2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (x) x^{2}) = 0

x \to 0 - lim (ln (x) x^{2}) =

Does not exist

= Does not exist

x \to 1 lim (\frac{2 x + 4}{x - 1})

x \to - 2 + lim (\frac{2 - x}{x ^{2} - 4})

x \to 1 lim (1 - 2 x)

x \to a lim (6 x^{2} - 3 x + 2)

x \to 0 lim (3 x + 1 - 1)

What is the limit as x approaches 0 of ln(x)x^2 ?
The limit as x approaches 0 of ln(x)x^2 is Does not exist