What is the limit as x approaches 0 of ln(sqrt(x)+1) ?

The limit as x approaches 0 of ln(sqrt(x)+1) is 0

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limit as x approaches 0 of ln(sqrt(x)+1)

x \to 0 lim (ln (x + 1))

0

Solution steps

x \to 0 lim (ln (x + 1))

Plug in the value

x = 0

= ln (0 + 1)

Simplify

ln (0 + 1) : 0

= 0

x \to 2 - lim (\frac{x}{x + 2})

x \to 0 lim (arctan (\frac{2}{x}))

x \to 4 lim (\frac{x ^{2} - 1}{x - 1})

x \to - 2 lim (- 1)

x \to 6 lim (cos (\frac{1}{x} - \frac{1}{6}))

What is the limit as x approaches 0 of ln(sqrt(x)+1) ?
The limit as x approaches 0 of ln(sqrt(x)+1) is 0