What is the limit as x approaches 0 of sin^x(1/x) ?

The limit as x approaches 0 of sin^x(1/x) is Does not exist

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limit as x approaches 0 of sin^x(1/x)

x \to 0 lim (sin^{x} (\frac{1}{x}))

Does not exist

Solution steps

x \to 0 lim (sin^{x} (\frac{1}{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (sin^{x} (\frac{1}{x})) =

Does not exist

x \to 0 - lim (sin^{x} (\frac{1}{x})) = 1

= Does not exist

x \to 1 + lim (3 - x)

x \to 2 lim (x^{2} - 5 x + 3)

x \to 0 lim (\frac{1 + x ^{2}}{x})

x \to 5 lim (4 x - 2)

x \to - \infty lim (x^{7})

What is the limit as x approaches 0 of sin^x(1/x) ?
The limit as x approaches 0 of sin^x(1/x) is Does not exist