What is the limit as x approaches-1-of (-1)/(x+1)-1 ?

The limit as x approaches-1-of (-1)/(x+1)-1 is infinity

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limit as x approaches-1-of (-1)/(x+1)-1

x \to - 1 - lim (\frac{- 1}{x + 1} - 1)

\infty

Solution steps

x \to - 1 - lim (\frac{- 1}{x + 1} - 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - 1 - lim (\frac{- 1}{x + 1}) - x \to - 1 - lim (1)

x \to - 1 - lim (\frac{- 1}{x + 1}) = \infty

x \to - 1 - lim (1) = 1

= \infty - 1

Apply Infinity Property:

\infty - c = \infty

= \infty

x \to 2 lim (ln (3 - x))

x \to 0 + lim (x^{2} \cdot e^{\frac{1}{x}})

x \to 0 lim (x^{2} - x + 1)

x \to 1 lim (csc (π x) ln (x))

t \to 0 + lim (t ln (t))

What is the limit as x approaches-1-of (-1)/(x+1)-1 ?
The limit as x approaches-1-of (-1)/(x+1)-1 is infinity