limit as x approaches-1+of (|x+1|)/(x+1)

Lösung

x \to - 1 + lim (\frac{∣ x + 1 ∣}{x + 1})

1

Schritte zur Lösung

x \to - 1 + lim (\frac{∣ x + 1 ∣}{x + 1})

x + 1

ist positiv wenn

x \to - 1 +

. Deshalb

∣ x + 1 ∣ = x + 1

= x \to - 1 + lim (\frac{x + 1}{x + 1})

Vereinfache

= x \to - 1 + lim (1)

x \to a lim c = c

= 1

x \to 7 lim (x - 2)

x \to 0 lim (f (a x))

x \to 0 lim (2 - 8 x + 5 x^{2})

x \to 0 - lim (\frac{e ^{x}}{e ^{x} - 1})

x \to 0 lim (3^{x} - 1)