What is the limit as x approaches-infinity of 2^{2x} ?

The limit as x approaches-infinity of 2^{2x} is 0

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limit as x approaches-infinity of 2^{2x}

x \to - \infty lim (2^{2 x})

0

Solution steps

x \to - \infty lim (2^{2 x})

Simplify

2^{2 x} : 4^{x}

= x \to - \infty lim (4^{x})

Apply the common limit:

x \to - \infty lim (a^{x}) = 0, a > 1

= 0

x \to 0 lim (\frac{\frac{1}{x}}{1})

x \to \infty lim (- 12 x^{5})

x \to 2 + lim (\frac{2 - x}{∣ 2 - x ∣})

x \to - 1 lim (x^{2} + 2 x + 1)

x \to 5 lim (x^{2} - 10)

What is the limit as x approaches-infinity of 2^{2x} ?
The limit as x approaches-infinity of 2^{2x} is 0