What is the limit as x approaches-2 of 1/((x+2)) ?

The limit as x approaches-2 of 1/((x+2)) is diverges

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limit as x approaches-2 of 1/((x+2))

x \to - 2 lim (\frac{1}{( x + 2 )})

diverges

Solution steps

x \to - 2 lim (\frac{1}{x + 2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 2 + lim (\frac{1}{x + 2}) = \infty

x \to - 2 - lim (\frac{1}{x + 2}) = - \infty

= diverges

x \to - 3 lim (\frac{1}{( x + 3 ) ^{4}})

x \to 0 lim (\frac{1 - x ^{2}}{x})

x \to 0 lim (e^{\frac{1}{x}} \cdot x)

x \to \infty lim (- e^{0})

x \to 2 lim (\frac{1}{x ^{8.132}})

What is the limit as x approaches-2 of 1/((x+2)) ?
The limit as x approaches-2 of 1/((x+2)) is diverges