What is the limit as x approaches-1+of (4-x)/(x+1) ?

The limit as x approaches-1+of (4-x)/(x+1) is infinity

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limit as x approaches-1+of (4-x)/(x+1)

x \to - 1 + lim (\frac{4 - x}{x + 1})

\infty

Solution steps

x \to - 1 + lim (\frac{4 - x}{x + 1})

\frac{4 - x}{x + 1} = (4 - x) \frac{1}{x + 1}

= x \to - 1 + lim ((4 - x) \frac{1}{x + 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to - 1 + lim (4 - x) \cdot x \to - 1 + lim (\frac{1}{x + 1})

x \to - 1 + lim (4 - x) = 5

x \to - 1 + lim (\frac{1}{x + 1}) = \infty

= 5 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

x \to 0 lim (ln (3^{x}))

x \to 2 lim (\frac{x - 4}{2 - x})

h \to 0 lim (\frac{cos ( x )}{h})

x \to 1 lim (x^{5} - 1)

x \to 0 lim (\frac{2 2}{x})

What is the limit as x approaches-1+of (4-x)/(x+1) ?
The limit as x approaches-1+of (4-x)/(x+1) is infinity