derivative of (3x-2^2(2x+1)^4)

Lösung

\frac{d}{d x} ((3 x - 2)^{2} (2 x + 1)^{4})

6 (3 x - 2) (2 x + 1)^{4} + 8 (2 x + 1)^{3} (3 x - 2)^{2}

Schritte zur Lösung

\frac{d}{d x} ((3 x - 2)^{2} (2 x + 1)^{4})

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (3 x - 2)^{2}, g = (2 x + 1)^{4}

= \frac{d}{d x} ((3 x - 2)^{2}) (2 x + 1)^{4} + \frac{d}{d x} ((2 x + 1)^{4}) (3 x - 2)^{2}

\frac{d}{d x} ((3 x - 2)^{2}) = 6 (3 x - 2)

\frac{d}{d x} ((2 x + 1)^{4}) = 8 (2 x + 1)^{3}

= 6 (3 x - 2) (2 x + 1)^{4} + 8 (2 x + 1)^{3} (3 x - 2)^{2}

\frac{\partial}{\partial x} (4 x^{2} + 4 y^{2})

\int 5 x + 2 d x

\int_{2}^{9} (x^{3} - π x^{2}) d x

t an g e n t f (x) = 8 (e^{x} + e^{x} x), at x = 0

y^{^{'}} = \frac{x}{( 1 + 2 y )}