What is the d/(dt)(2cos(12t)) ?

The d/(dt)(2cos(12t)) is -24sin(12t)

What is the first d/(dt)(2cos(12t)) ?

The first d/(dt)(2cos(12t)) is -24sin(12t)

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\frac{d}{d t} (2 cos (12 t))

- 24 sin (12 t)

Solution steps

\frac{d}{d t} (2 cos (12 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (cos (12 t))

Apply the chain rule:

- sin (12 t) \frac{d}{d t} (12 t)

= - sin (12 t) \frac{d}{d t} (12 t)

\frac{d}{d t} (12 t) = 12

= 2 (- sin (12 t) \cdot 12)

Simplify

= - 24 sin (12 t)

\frac{( x ^{2} - 2 x )}{( x - 1 ) ^{2}}

y = \frac{2 x ^{2} - x + 4}{x}

(cos^{22} (x)) (1 - x)^{- 2}

x (x^{2} - 1)^{\frac{1}{2}}

\frac{( 4 x ^{3} - 5 x - 3 )}{( 2 x )}

What is the d/(dt)(2cos(12t)) ?
The d/(dt)(2cos(12t)) is -24sin(12t)
What is the first d/(dt)(2cos(12t)) ?
The first d/(dt)(2cos(12t)) is -24sin(12t)